Since two letters are the same, you will divide n!, or the total number of letters in the word, by #n_1!(n_2!)#, etcetera, where #n_1# is the number of repeated letters in the word, and #n_2!# is another type of repeated letter, such as in the word ANNA, #n_1!# = 2! and #n_2!# = 2!, because there are 2 a's and 2 n's. Show
number of different words possible = #(4!)/(2!)#, since there are two o's in Ohio and therefore two repeated letters When calculated: = #24/2# = 12 So, 12 four word permutations are possible with the letters in the word Ohio. Exercises:
Hopefully you understand! Answer : 5040, 720 Solution : The given word contains 7 letters, which may be arranged themselves in 7! = 5040 ways. <br> The given word contains 3 vowels and 4 consonants. <br> Taking the 3 vowels EAO as one letter, this letter and 4 more letters can be arranged in 5! = 120 ways. <br> The 3 vowels can be arranged among themselves in 3! = 6 ways. <br> Required number of arrangements with vowels together `=(120 xx 6)=720.` ANS. 120c) How many of these permutations start with the letter “M” and ends with2 Get answer to your question and much more Example 4.2 :Evaluate the following.. Get answer to your question and much more Example 5:How many four-letter permutations can be formed from the letters inthe word “heptagon”?! Get answer to your question and much more End of preview. Want to read all 3 pages? Upload your study docs or become a Course Hero member to access this document Tags Numerical digit, 3 digits, 7 digit, five digit
Question 891677: In how many ways can the letters of HEPTAGON be permuted so that the vowels are never separated? Answer by Edwin McCravy(19236)  You can put this solution on YOUR website! Example: NHEOATGP That example has the vowel sequence EOA The vowels {A,E,O} can be arranged together in any of 3! ways. For each of those 3! ways, we can form the permutation of these 6 things: H,P,T,G,N,(vowel sequence) in 6! ways. Answer: 3!6! = 6*120 = 720 ways. Edwin 3. How many four-letter permutations can be formed from the letters in the word HEPTAGON? A.32 B.168 C.860 D. 1680 4. A poker hand consists of five cards dealt from an ordinary deck of 52 playing cards. How many possible poker hands are there? A. 598960 B. 1598960 C. 2980560 D. 2598960 5. A chef can prepare 20 different dinners. In how many ways can he select 6 cf them for today's menu? A. 8760 B. 38760 C. 67380 D. 78630Question Gauthmathier2230Grade 8 · 2021-05-27 YES! We solved the question! Check the full answer on App Gauthmath 3. How many four-letter permutations can be formed from the letters in the word HEPTAGON?
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How many four letter permutations can be formed from the letters in the word hexagon?= 5040 ways. <br> The given word contains 3 vowels and 4 consonants.
How many permutations of 4 different letters are there?Assume non-sensical words count, i.e. "dnts" would count as a 4-letter word for our purposes. Explanation: This is a permutation of 26 letters taken 4 at a time. To compute this we multiply 26 * 25 * 24 * 23 = 358,800.
How many different four letter permutations can be formed from the letters in the word triangle?Ways to arrange the other four letters. So there are a total of 3! X 2 x 4! = 288 ways to arrange the letters of TRIANGLE as specified.
How many different permutations can be formed from the word exam?Hence we have 6×3=18 words of this type. ∴ 2454 different permutations can be formed from the letter of the word EXAMINATION taken four at a time.
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