Q. How Many 6−Digit Numbers are There in All?Ans. The smallest digit in the highest place value is 0, which cannot be used. As a result, the highest place value can be 1, the second smallest digit. Show
100000 is the smallest six-digit number. We all know that the largest digit is nine and can be used everywhere. 999999 is the largest six-digit number. When it comes to AP (Arithmetic progression) 100000 for the first phrase (a). 999999 is the last term. One is the difference (d). The nth term is calculated using the formula. a = a + (n – 1)d 100000 + (n – 1) = 999999 n – 1 = 899999 n = 900000 ∴ In total, there are 900,000 6-digit numbers. OR The largest 6−digit number is 999999 The smallest 6−digit number is 100000 Hence, total number of 6−digit numbers =(999999−100000)+1 =899999+1 =900000 =9lakhs OR Calculate the total number of 6-digit numbers in all using the permutation idea. First, we’ll determine the number of options for the 6-digit number’s first place digit. The permutation will then be used to determine the number of options available for the remaining digits of the 6-digit number. The total number of 6-digit numbers will be determined by solving this. It is assumed that the numbers are six digits. So, we know that there are only nine options for the first place digits in a six-digit number, i.e. 1,2,3,4,5,6,7,8,9 because 0 cannot be in the first place digit. After all, the number will become a five-digit number. As a result, the total number of permutations for the six-digit integer’s initial digit is = ₉P₁ = 9!/(9−1)! =9 Now we know that there are ten options for the remaining five digits in the six-digit number, namely 0,1,2,3,4,5,6,7,8,9. Total number of permutations for the six-digit number’s remaining five digits = ₁₀P₁=10!/(10−1)! =10 So, the total number of 6 digit numbers in all =9×10×10×10×10×10=900000 Therefore, there is a total of 9,00,000 6-digit numbers. Sum How many 7-digit numbers are there in all? Advertisement Remove all ads SolutionThe largest seven-digit number = 9999999 Concept: Comparing Numbers Is there an error in this question or solution? Advertisement Remove all ads Chapter 1: Number System - Test paper 1 [Page 21] Q 5Q 4Q 6 APPEARS INRS Aggarwal Class 6 Mathematics Chapter 1 Number System Video TutorialsVIEW ALL [1]
Advertisement Remove all ads Numbers up to 6 digits are natural numbers that have the place value till hundreds, thousands, or lakhs. Answer: There are 9,00,000 (nine lakh) 6-digit numbers in all.In the 6-digit numbers, the highest place value is 1,00,000 which has a unique name in the Indian numeral system – a lakh. Explanation: To find the total number of 6-digit numbers, let's first find the smallest and the largest 6-digit number. Smallest 6-digit number: 1,00,000 Largest 6-digit number: 9,99,999 Total number of 6 digit numbers = (9,99,999 - 1,00,000) + 1 = 9,00,000 Therefore, there are 9 lakh 6-digit numbers in all.How many 7 digits are there in all?Hence, answer is 90,00,000.
How many 8 digit numbers are there in all for Class 6?Therefore, 90000000 eight digit numbers are there in all.
How many 6 digit even numbers can be formed from digits 1 to 7?= 720 ways. Therefore, 720, six digit even numbers can be formed.
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