How many ways can you choose a manager and assistant from 9 person task force use permutation?

1) Solve for the factorials below:

a) 4!

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24


b) 0!

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1


c) (3!)(2!)

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12


d) 10!/8!

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90


2) Evaluate each:

a) 9P9

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9!=362,280


b) 9C9

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1


c) 9P5

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15,120


d) 9C5

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126



Be careful, I mixed in some problems that are not Permutation/Combination into the below set.

3) How many ways can you turn in a batting order for a baseball team if you only have 9 players?

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9P9=362,280


4) Suppose a lawyer must select 4 jurors from a set of six candidates? How many groups are possible?

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6C4=60


5) How many ways can 3 runners be selected for the Olympics from a field of 5 contestants?

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5C3=10


6) How many ways can the first 3 places be awarded in a race involving  5 contestants (excluding ties)?

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5P3=60


7) How many ways can the positions of president and vice president be assigned from a group of 8 people?

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8P2=56


8) Find  the Number of hugs possible in a family of 5 people (no repeat hugs).

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5C2=10


9) You have 9 families you would like to invite to a wedding. Unfortunately, you can only invite 6 families. How many different sets of invitations could you write?

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9C6=84


10) Suppose we have to select 5 managers from a list of 10. How many ways can this be done? Give the correct expression that gives the answer.

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10C5


11) Suppose we have to select a manager, assistant manager, and night manager from a list of 10 people. How many ways can this be done? Give the correct expression that gives the answer.

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10P3


12) How many ways can a 3-card hand be selected from a standard 52-card deck? Give the correct expression that gives the answer.

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52C3


13) Three cards are selected randomly and given to 3 players. How many possibilities exist? Give the correct expression that gives the answer.

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52P3


14) A card is select from a standard deck of cards, then put back and the deck is shuffled. This is done 3 times. How many 3-card hands can you receive?

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52*52*52=140,608


15) At a Fiat dealership a total of 3 cars of a particular model must be transported to another dealership. If there are 25 cars of this type, how many choices are available for transport?

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25C3=2300


16) At a Fiat dealership a total of 3 cars of a particular model must be transported to another dealership. If there are 25 cars of this type, how many ways can they be loaded onto the truck for transport?

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25P3=13,800


17) At a Fiat dealership there are 25 cars of a certain model. Fifteen have automatic transmission. Twelve have leather seats. Ten cars have both automatic transmission and leather seats.

a) How many have either automatic transmission or leather seats.

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17


b) How many have neither automatic transmission nor leather seats.

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8


18) Social Security numbers consist of 9 digits (0-9). If there are no restrictions, how many different social security numbers are possible?

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10*10*10*10*10*10*10*10*10=109 =1,000,000,000


19) Suppose license plates in one state have 4 letters followed by 2 digits.

a) How many license plates can be created if there are no other restrictions?

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(264)(102)=45,687,600


b) What if only letters cannot be repeated?

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26(25)(24)(23)(102)=35,880,000


c) What if only digits cannot be repeated?

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(264)(10)(9)= 41,127,840


20) A shipment of 20 disk drives were received by a computer store. Four of the drives are defective. A sample of 2 are selected randomly.

a) How many different samples can be selected?

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Combination Problem: 20C2=190


b) How many of the samples contain 2 defective drives?

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Combination Problem: 4C2=6


c) Suppose one of the samples is tested and one sample is sold. How many ways can this be done?

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Permutation Problem: 20P2=380


21) Suppose a 5-card hand is selected from a standard deck of cards. How many ways can the following be done?

a) Select 3 Kings and 2 Aces

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(4C3)(4C2)=4(6)=24


b) Select exactly 3 fours.

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(4C3)(48C2)=4(1128)=4512


c) At least 4 hearts

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27885+1287=29,172


22)  Suppose we have an office of 5 women and 6 men and need to select a 4 person committee. How many ways can we select

a) 2 men and 2 women?

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(5C2)(6C2)=150


b) 3 men and 1 woman?

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(5C3)(6C1)=60


c) All women?

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(5C0)(6C4)=15 or just 6C4=15


23) . A lottery consists of 54 numbers. To purchase a ticket, you select 6 numbers from 54 without repetition. How many selections are possible? (In lotteries, the order is generally not relevant.)

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54C6=25,827,165


Just for fun, what if you had to get the numbers in the order selected?

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54P6=18,595,558,800 (don't hold your breath)


24) Out of 30 applicants, 11 are female, 17 are college graduates, 7 are bilingual, 3 are female graduates, 2 are bilingual women, 6 are bilingual graduates and 2 are bilingual female graduates. Find the number of female graduates that are not bilingual.

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1


25) a) How many 3 letter code words can be selected if there are no restrictions? b) How many 3 letter code words can be selected if repetition is not allowed?

Answer a)


17,576


Answer b)


15,600


26) Seven coins are tossed. How many different ways can they land?

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27 =128


27)

There are 7 women and 5 men in a class. The instructor must select 5 to be on a committee. How many ways can the instructor select,

a) a group of 3 women and 2 men?

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350


b) a group of 2 women and 3 men?

Show Answer


210


c) a group of all women?

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21


d) a group of all men?

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1



What does 10p5 mean Quizizz?

116280. 120 seconds. Q. What does 10P5 mean? Permutations with 5 choices and 10 positions.

How many ways can his coach choose five starting players?

How many different possible ways can the coach choose a team of 5 players? 12C5 = 792 ways the coach can choose a team of 5.

How many identification code are possible by using 3 letters if no letter may be repeated?

Thus there are 15,600 identification codes.