Given the names and grades for each student in a Physics class of N students, store them in a nested list and print the name(s) of any student(s) having the second lowest grade. Show
Nested list Hackerrank solution Given the names and grades for each student in a class of students, store them in a nested list and print the name(s) of any student(s) having the second lowest grade. Note: If there are multiple students with the second lowest grade, order their names alphabetically and print each name on a new line. ExampleThe ordered list of scores is , so the second lowest score is . There are two students with that score: . Ordered alphabetically, the names are printed as: Input FormatThe first line contains an integer, , the number of students. The subsequent lines describe each student over lines. - The first line contains a student's name. - The second line contains their grade. ConstraintsThere will always be one or more students having the second lowest grade. Output FormatPrint the name(s) of any student(s) having the second lowest grade in. If there are multiple students, order their names alphabetically and print each one on a new line. Sample Input 05 Harry 37.21 Berry 37.21 Tina 37.2 Akriti 41 Harsh 39 Sample Output 0Explanation 0There are students in this class whose names and grades are assembled to build the following list: python students = [['Harry', 37.21], ['Berry', 37.21], ['Tina', 37.2], ['Akriti', 41], ['Harsh', 39]] The lowest grade of belongs to Tina. The second lowest grade of belongs to both Harry and Berry, so we order their names alphabetically and print each name on a new line. Nested List Hackerrank Solution in Python# nested list hackerrank solution # nested list hackerrank solution in python if __name__ == '__main__': students = [] scores = [] for N in range(int(input())): name = input() score = float(input()) scores.append(score) students.append([name, score]) count = scores.count(min(scores)) for i in range(count): scores.remove(min(scores)) secondHigh = min(scores) students.sort() output = [x for x in students if x[1] == secondHigh] for i in output: print(i[0]) # nested list hackerrank solution # nested list hackerrank solution in python - docodehere.com
Hey coders, today we are going to solve Nested Lists in Python Hacker Rank Solution. ProblemGiven the names and grades for each student in a class of N students, store them in a nested list and print the name(s) of any student(s) having the second lowest grade. Note: If there are multiple students with the second lowest grade, order their names alphabetically and print each name on a new line. Example records = [[ “chi”, 20.0]], [“beta”, 50.0], [“alpha”, 50.0] The ordered list of scores is [20.0, 50.0], so the second lowest score is 50.0. There are two students with that score: [“beta”, “alpha”]. Ordered alphabetically, the names are printed as: alpha betaInput FormatThe first line contains an integer, , the number of students.
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Output FormatPrint the name(s) of any student(s) having the second lowest grade in. If there are multiple students, order their names alphabetically and print each one on a new line. Sample Input 0 5 Harry 37.21 Berry 37.21 Tina 37.2 Akriti 41 Harsh 39Sample Output 0 Berry HarryExplanation 0 There are 5 students in this class whose names and grades are assembled to build the following list: python students = [[‘Harry’, 37.21], [‘Berry’, 37.21], [‘Tina’, 37.2], [‘Akriti’, 41], [‘Harsh’, 39]] The lowest grade of 37.2 belongs to Tina. The second lowest grade of 37.21 belongs to both Harry and Berry, so we order their names alphabetically and print each name on a new line. Solution – Nested Lists in Python – Hacker Rank SolutionResult =[] scorelist = [] if __name__ == '__main__': for _ in range(int(input())): name = input() score = float(input()) Result+=[[name,score]] scorelist+=[score] b=sorted(list(set(scorelist)))[1] for a,c in sorted(Result): if c==b: print(a)Disclaimer: The above Problem (Nested List) is generated by Hacker Rank but the Solution is provided by CodingBroz. This tutorial is only for Educational and Learning purposes. |