Answer is : D. (0, 3/2) ∪ (3, ∞) Show ⇒ f(x) = [x(x - 3)]2 ⇒ f'(x) = 2[x(x - 3)] = 0 ⇒ x = 3 and x = 3/2 When x > 3/2 the function is increasing x < 3 function is increasing. ⇒ (0, 3/2) ∪ (3, ∞) Function is increasing. Is a function increasing if derivative is 0?If the derivative happens to be zero then the function is constant, neither increasing nor decreasing. Example 1: In the given graph of the function f(x), determine the interval(s) where the function is increasing, decreasing, or constant.
Is X² an increasing function?So your function f(x)=x2 defined on the domain [0,∞) is strictly increasing.
When can we say that a function is strictly increasing?Strictly Increasing Function - A function f(x) is said to be strictly increasing on an interval I if for any two numbers x and y in I such that x < y, we have f(x) < f(y).
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