What will be the difference between simple interest and compound interest on sum of Rs?

Solution : Principal `(P)=Rs.50000`<br>Rate `(R)=10%` p.a<br>Time`(n)=2`years<br>Amount `(A)=P(1+R/100)^n`<br>`=Rs.50000(1+10/100)^2`<br>`=Rs.50000(11/10)^2`<br>`=Rs.50000×11/10×11/10`<br>`=Rs.60500`<br>`:.`Compound interest `(C.I.)=A-P`<br>`=Rs.60500-Rs.50000`<br>`=Rs.10500`<br>Simple Interest `(S.I.)`<br>`=(PxxRxxT)/100=Rs.(50000xx10xx2)/100`<br>`=Rs.10000`<br>Difference between `C.I.` and `S.I.`<br>`=Rs.10500-Rs.10000`<br>`=Rs.500`<br>`therefore` The difference between `C.I.` and `S.I.` is `Rs.500`.

What will be the difference between simple interest and compound interest on sum of Rs?

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  • Compound Interest Exercise 14.1
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  • Compound Interest Exercise 14.5

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RD Sharma Solutions Class 8 Mathematics Solutions for Compound Interest Exercise 14.2 in Chapter 14 - Compound Interest

Question 36 Compound Interest Exercise 14.2

The difference between the compound interest and simple interest on a certain sum for 2 years at 7.5% per annum is Rs. 360. Find the sum.

Answer:

Given,

Time = 2 years

Rate = 7.5 % per annum

Let principal = Rs P

Compound Interest (CI) – Simple Interest (SI) = Rs 360

C.I – S.I = Rs 360

By using the formula,

P [(1 + R/100)^n - 1] – (PTR)/100 = 360

P [(1 + 7.5/100)^2 - 1] – (P(2)(7.5))/100 = 360

P[249/1600] – (3P)/20 = 360

249/1600P – 3/20P = 360

(249P-240P)/1600 = 360

9P = 360 × 1600

P = 576000/9

= 64000

∴ The sum is Rs 64000

Video transcript

hello everybody welcome to leader learning my name is rajna chaudhary and we have to write this statement in the equation form it is written that write equation for the statements for these statements so statement is one fourth of a number x minus g minus four gives four so one fourth of a number x would be one fourth of x that mean the value of this part is 1 by 4 of x then we have to minus 4 from it so let's minus 4 from it so minus 4 and gives gives means is equal to 4 so this is the equation for the statement we can write it like that at the place of off we can write multiply then minus 4 is equal to 4. we can also write it like x upon 4 minus 4 is equal to 4. so this is the form of equation for the statement i hope you understand the method see you in my next video don't forget to like comment and subscribe leader learning channel thank you for watching

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What will be the difference between simple interest and compound interest on sum of Rs?

What will be the difference between the compound interest (interest is compounded annually) and simple interest on a sum of Rs. 6400 at the rate of 10% per annum for 2 years?

  1. Rs. 90
  2. Rs. 72
  3. Rs. 128
  4. Rs. 64

Answer (Detailed Solution Below)

Option 4 : Rs. 64

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History of Indian Constitution

15 Questions 15 Marks 9 Mins

CONCEPT:

The simple interest is given as \(SI = \frac{{Prt}}{{100}}\) and the compound interest is given as \(CI = P{\left( {1\; + \;\frac{r}{{100}}} \right)^t} - P\) where P is the prinicipal amount, r is the interest rate and t is the time in years.

EXPLANATION:

The difference between the simple interest and compound interest can be given by:

CI – SI

⇒ \(\left[ {\;P{{\left( {1 + \frac{r}{{100}}} \right)}^t} - P} \right] - \;\frac{{Prt}}{{100}}\)

CALCULATION:

SI = (PRT/100)

⇒ (6400 × 10 × 2)/100

⇒ 128000/100

⇒ 1280

\(CI = P{\left( {1\; + \;\frac{r}{{100}}} \right)^t} - \;P\;\)
\( \Rightarrow \;6400{\left( {1\; + \;\frac{{10}}{{100}}} \right)^2} - 6400\)

⇒ 6400(1 + 0.1)2 – 6400

⇒ 6400(1.1)2 – 6400

⇒ (6400 × 1.21) – 6400

⇒ 7744 – 6400

⇒ 1344

CI – SI

⇒ 1344 – 1280 = 64

⇒ Required difference = Rs. 64

Hence D is the correct answer.

Smart Trick

Effective rate difference for 2 years = (r2/100) = (102/100) = 1%

∴ Required difference = 1% of 6400 = 6400 × (1/100) = 64.

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